Given an array nums with n objects colored red, white, or blue, sort them in-place so that objects of the same color are adjacent, with the colors in the order red, white, and blue.
Here, we will use the integers 0, 1, and 2 to represent the color red, white, and blue respectively.
Follow up:
- Could you solve this problem without using the library's sort function?
- Could you come up with a one-pass algorithm using only O(1) constant space?
Example 1:
Input: nums = [2,0,2,1,1,0] Output: [0,0,1,1,2,2]
Example 2:
Input: nums = [2,0,1] Output: [0,1,2]
Example 3:
Input: nums = [0] Output: [0]
Example 4:
Input: nums = [1] Output: [1]
Constraints:
- n == nums.length
- 1 <= n <= 300
- nums[i] is 0, 1, or 2.
문제 풀이:
- 쉬웠음
- 버블소트 사용
class Solution {
public:
void sortColors(vector<int>& nums) {
int len= nums.size();
for(int i=0; i<len-1; i++){
for(int j=0; j<len-1 - i; j++){
if(nums[j] > nums[j+1]){
int tmp = nums[j];
nums[j] = nums[j+1];
nums[j+1] = tmp;
}
}
}
}
};
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